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30y^2-31y-6=0
a = 30; b = -31; c = -6;
Δ = b2-4ac
Δ = -312-4·30·(-6)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-41}{2*30}=\frac{-10}{60} =-1/6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+41}{2*30}=\frac{72}{60} =1+1/5 $
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